Hi all...
My challenge is to write a routine which will translate correctly (in all circumstances) pow functions as done in C.
The winner we judged on two things.
1) Translations must be correct
2) Efficiency
Example:
Basic
r1 = (-c + (SQR(b(x) ^ 2 - (4 * a * c)))) / (2 * a)
C
r1 = (-c + (sqrt(pow(b(x), 2) - (4 * a * c)))) / (2 * a)
Good luck!
Fronrunner
Sounds like an interesting, if quite specific, challenge. Its too bad I'm busy at the moment as I have always wanted to get around to writing parsers.
That's right, it is quite specific but a general parser would be too easy for a challenge :
Cheers,
Frontrunner
Hopefully I can get some time to have a go, seems straight forward enough but will see.
I am looking forward to see your contribution!
Cheers,
Frontrunner
Could you please be patient with me and tell me what POW stands for? The only meaning I have for those three letters at present is, Prisoner Of War, and, I'm sure, that is not what is intended.Â
Hi Ralph,
Sure I will try to explain you what POW means:
Like in qbasic there is in C a mathematical function to compute the power exponent.
In qbasic we use ^ but in C it is called POW.
I will give some more example in both C and bqasic so you can see the differences.
Example in C
 printf ("7 ^ 3 = %lf\n", pow (7,3));
 printf ("4.73 ^ 12 = %lf\n", pow (4.73,12));
 printf ("32.01 ^ 1.54 = %lf\n", pow (32.01,1.54));
Example in qbasic
 print "7 ^ 3 = ", 7 ^ 3
 print "4.73 ^ 3 = ", 4.73 ^ 12
 print "32.01 ^ 1.54 = ", 32.01 ^ 1.54
Both should output something like this:
7 ^ 3 = 343.000000
4.73 ^ 12 = 125410439.217423
32.01 ^ 1.54 = 208.036691
Please forget the C syntax you see in the example.
A correct translation (according to this challenge) should translate print 3 ^ 7 to print pow(3,7).
Now this looks easy but things start to get more complicated when translating
print (10 ^ 2) - 5 + (21 * (3 - 4 ^ 6) * 2 + 10 - 5) ^ 2 + 3 - (3 + 7) + 99
To
print pow(10,2))-5+pow((21*(3-pow(4,6))*2+10-5),2)+3-(3+7)+99)
I hope that helped a little.
Kind regards,
Frontrunner
Frontrunner:
Yes, I now understand what your challenge is all about; translating a qb expression with a power expression into its equivalent code in C.Â
I am not into C, so, I can not compete. But, I know that others will!
Hi Ralph,
You are to some part right!
But please forget about the C part, as long as the POW and the ^ operator are being translated correctly.
I am not here on a qbasic forum for C codingÂ
Cheers,
Frontrunner
I'm trying to dust off my head and have a go, I know its about parsing correcting but am confused by your original example:
r1 = (-b + (SQR(b(x) ^ 2 - (4 * a * c)))) / (2 * a)
Is b and b(x) an integer and an arrary respectively or am I miss reading, I've been out of maths and coding for too long