09-02-2003, 06:08 AM
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09-02-2003, 06:13 AM
This doesn't even deserve a response, but I just have to say this:
yu0 isz r3+4|2d
yu0 isz r3+4|2d
09-02-2003, 06:22 AM
ALEIN!!!!
09-02-2003, 07:49 AM
Code:
3 + 3 = 6
6 - 3 = 3
3 * 3 = 9
9 / 3 = 3
3 + 3 - 3 * 3 / 3 = 3Most of what you have there would be true for any number. The second line is just the inverse of the first, and the fourth is the inverse of the third. In the fifth the added and subtracted terms are equal, so you are adding 0, and you don't change the original value.
You have more ones than I have threes because one is the multiplicative identity (this just means that any number is left unchanged when multiplied it by one)
09-02-2003, 07:52 AM
3 + 3 - 3 * 3 / 3 = -1
(6 - 9) / 3 = -1
-3 / 3 = -1
jeez.
(6 - 9) / 3 = -1
-3 / 3 = -1
jeez.
09-02-2003, 08:02 AM
Ninkazu,
use proper order of operations. Multiplication and division come before addition and subtraction (you may have been taught PEMDAS).
If you are not sure about this, try
use proper order of operations. Multiplication and division come before addition and subtraction (you may have been taught PEMDAS).
Code:
3 + 3 - 3 * 3 / 3
= 3 + 3 - 9 / 3
= 3 + 3 - 3
= 3 + 0
= 3If you are not sure about this, try
Code:
IF 3 + 3 - 3 * 3 / 3 = 3 THEN PRINT "It's true"09-02-2003, 08:05 AM
so you see my observation is correct
09-02-2003, 08:44 AM
WhiteTiger,
You forgot:
N^0 = 1
where N can be any number.
*****
You forgot:
N^0 = 1
where N can be any number.
*****
09-02-2003, 10:53 AM
uh..what are you trying to get at that i dont see
09-02-2003, 11:25 AM
Well done, you've just proved that 1=1, I'm sure, however, that that fact has already been proven by far smarter brains than ours.
Here, lets prove something a little more complicated: .9(recuring) = 1
n = .9(recuring)
10n = 9.9(recuring)
9n = 8.9(recuring) (subtract this line from line 2)
n = 1
Now, who can prove that the square root of 2 cannot be written in the ratio of two integers? That's a little more tricky, but let's do the easy ones first.
Here, lets prove something a little more complicated: .9(recuring) = 1
n = .9(recuring)
10n = 9.9(recuring)
9n = 8.9(recuring) (subtract this line from line 2)
n = 1
Now, who can prove that the square root of 2 cannot be written in the ratio of two integers? That's a little more tricky, but let's do the easy ones first.
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