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Make an algorithm that, given a bunch of (n) random INTEGERs and two inputted (sp??) LONGs, where the sum of the LONGs equals the sum of the integers,

finds the combination of INTEGERs for each LONG that most closely approximate (or exactly equal) the LONG's individual values.

Example:

INTEGERS: 5 4 2 3 = 14
LONGs: 6 8

Solution:
4 2, 5 3

Most efficient (or, the one that actually works, if there is only one that works..) algorithm wins...
let's say the two longs = 10, 8
and the integers are 7, 2, and 9

both sets sum 18

would you want the program to say "7+2, 9" or "9+2, 7"? Both return answers (9, 9) or (11, 7) that are one away from correct.

*peace*

Meg.

p.s. cool challenge Wink
heh. Good question.

Just any equivalent answer will do.

You could just display all equivalent answers. That would be even cooler.
*swats the flies and gets rid of the giant dust balls*
Quote:*swats the flies and gets rid of the giant dust balls*

Need some help there? I've got a vacuum Wink
Aga, I had such a question on a programming tournament (olympiad) once, and the answer is just like:

Code:
[pseudocode]
do
   do
      give highest number from the stack
   loop all groups
   do
      give lowest number from the stack
   loop all groups
loop all available 'stack-numbers'
[/pseudocode]

I got many points on that question Wink
I don't get it.
First you divide all highest numbers to all groups, then you divide all lowest numbers to each group. That should give a good answer. This is a global algorithm, there could be better answers, but take a look:

LONGs: 8, 6
INTs: 5, 4, 3, 2

My algo: 5 + 2 = 7 and 4 + 3 = 7
One-of-a-time algo: 5 + 3 = 8, 4 + 2 = 6

But take a look: average of my algo is 7, the one of a time algo is 7 as well. Smile
How would it work with this:

100 500
200 100 195 15

?
This is my shot at it. It's probably not optimized, but it seems to work. My strategy is to only try to fit the smaller of the two longs, and I start with the biggest integers first.

If you want to try it with your own numbers, call GroupAddends with the longs in SUM(), the integers in Choices() (starting with Choices(1)), and the number of integers in n. The output is in Groups(), with the number of integers for the jth long in Groups(j, 0), and the integers starting from Groups(j, 1).

Code:
DEFINT A-Z

DECLARE SUB Sort (Array%(), n%)
DECLARE SUB GroupAddends (Sum() AS LONG, Choices%(), n%, Groups%(), Errr%)
DECLARE SUB FindAddends (Chcs%(), n%, BYVAL Total AS LONG, Sum AS LONG, Addends%(), Errr%)

DIM Sum(1) AS LONG, Total AS LONG

n = 14
DIM Choices(n), Groups(1, n)

CLS
RANDOMIZE TIMER

'------------- Generate & Display Numbers -----------------
Adds0 = INT(RND * (n - 1) + 1)

FOR j = 1 TO n
  Choices(j) = INT(RND * 1000 + .5)
  PRINT Choices(j);
  IF j <= Adds0 THEN
    Sum(0) = Sum(0) + Choices(j)
    IF j < Adds0 THEN
      PRINT "+";
    ELSE
      PRINT "="; Sum(0)
    END IF
  ELSE
    Sum(1) = Sum(1) + Choices(j)
    IF j < n THEN
      PRINT "+";
    ELSE
      PRINT "="; Sum(1)
    END IF
  END IF
NEXT
PRINT
'------------ End of Genrate & Display Numbers ------------

GroupAddends Sum(), Choices(), n, Groups(), Errr

'-------------------  Display Results  --------------------
FOR i = 0 TO 1
  Total = 0
  FOR j = 1 TO Groups(i, 0) - 1
    Total = Total + Groups(i, j)
    PRINT Groups(i, j); "+";
  NEXT
  Total = Total + Groups(i, j)
  PRINT Groups(i, j); "="; Total
NEXT
PRINT "Error ="; Errr
'-------------------- End of Display results --------------

SUB FindAddends (Chcs(), n, BYVAL Total AS LONG, Sum AS LONG, Addends(), Errr)
  DIM Adds(n)
  Errr = 10000
  j = n
  DO
    IF Total <= Sum THEN
      IF Sum - Total < Errr THEN
        Errr = Sum - Total
        Addends(0) = j
        FOR i = 1 TO j
          Addends(i) = Chcs(i)
        NEXT
      END IF
      EXIT SUB
    ELSE
      Total = Total - Chcs(j)
      IF Chcs(j) < Sum THEN
        FindAddends Chcs(), j - 1, Total, Sum - Chcs(j), Adds(), NewEr
        IF Sum - Chcs(j) < NewEr THEN
          IF Sum - Chcs(j) < Errr THEN
            Addends(0) = 1
            Addends(1) = Chcs(j)
            Errr = Sum - Chcs(j)
          END IF
        ELSEIF NewEr < Errr THEN
          Errr = NewEr
          Addends(0) = Adds(0) + 1
          FOR i = 1 TO Adds(0)
            Addends(i) = Adds(i)
          NEXT
          Addends(Addends(0)) = Chcs(j)
          IF NewEr = 0 THEN EXIT SUB
        END IF
      ELSE
        IF Chcs(j) - Sum < Errr THEN
          Errr = Chcs(j) - Sum
          Addends(0) = 1
          Addends(1) = Chcs(j)
        END IF
        IF Chcs(j) = Sum THEN EXIT SUB
      END IF
    END IF
    j = j - 1
  LOOP WHILE j > 0
END SUB

SUB GroupAddends (Sum() AS LONG, Choices(), n, Groups(), Errr)
  DIM Addends(n), Total AS LONG
  Sort Choices(), n
  Smaller = -(Sum(1) < Sum(0))
  Total = Sum(0) + Sum(1)
  FindAddends Choices(), n, Total, Sum(Smaller), Addends(), Errr

  CIndex = 1
  GIndex = 0

  Groups(Smaller, 0) = Addends(0)
  Groups(1 - Smaller, 0) = n - Addends(0)

  FOR j = 1 TO Addends(0)
    WHILE Addends(j) > Choices(CIndex)
      GIndex = GIndex + 1
      Groups(1 - Smaller, GIndex) = Choices(CIndex)
      CIndex = CIndex + 1
    WEND
    Groups(Smaller, j) = Addends(j)
    CIndex = CIndex + 1
  NEXT

  IF CIndex <= n THEN
    FOR j = CIndex TO n
      GIndex = GIndex + 1
      Groups(1 - Smaller, GIndex) = Choices(j)
    NEXT
  END IF
END SUB

SUB Sort (Array(), n)
  DO
    Changes = 0
    FOR j = 0 TO n - 1
      IF Array(j) > Array(j + 1) THEN
        SWAP Array(j), Array(j + 1)
        Changes = Changes + 1
      END IF
    NEXT
  LOOP WHILE Changes > 0
END SUB
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