Why doesn't this work?
IF amount$ = CHAR$(64-122) THEN
END
END IF
I am trying to get the program to end if you type a letter from the keybord. I already go it to end if you put nothing into it but now trying for letters.
What am I doing wrong :???:
IF amount$ = CHAR$(64-122) THEN
END
END IF
Alright, here's one of your problems: CHAR$ is not a function (at least not in QB). There is a CHR$ though.
Also, I assume you are trying to define a range of characters by putting CHAR$(64-122). What this actually does is
subtracts 122 from 64, which should give an error.
There are two ways of fixing this:
Code:
IF amount$ >= CHR$(64) AND amount$ <= CHR$(122) THEN
END
END IF
This tells says to end if amount$ has a alphabetical value between CHR$(64) and CHR$(122).
The second way:
Code:
SELECT CASE amount$
CASE CHR$(64) TO CHR$(122)
END
END SELECT
This, uses select case and a range to check the value. Both should work.
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Thank you
didn't realize I was subtracting the ASC value I was just trying to be in that range to eliminate the letters
Thanks again