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circle algorithm question - Agamemnus - 07-17-2006
Let's say I have a circle. The center has (x, y) coordinates (0, 0).
How do I determine the (x, y) coordinates of n points around the circumference of the circle spaced equally apart (along the circumference), assuming we start at a point (0, r), r being the radius?
Thanks....
circle algorithm question - Zap - 07-17-2006
Like this?
Code:
#define PI 3.141592
dim as double radians
dim as integer cx, cy, r, numPoints, px, py
screen 14
cx=150
cy=120
r=100
numPoints=10
for radians=0 to PI*2 step PI*2/numPoints
px=cx+cos(radians)*r
py=cy-sin(radians)*r
pset(px,py)
'or save coordinates here
'subtract cx and cy from px and py respectively to get
'coordinates relatively from (0, 0)
next radians
sleepcircle algorithm question - TheAdventMaster - 07-17-2006
This (basically the same as Zap's heheh)?
Code:
#define PI 3.141592
dim as double radians
dim as integer angle, r, px, py
screenres 640, 480
angle = 30
r=100
numPoints=10
Do
radians = angle * 3.14/180
px = r * cos(radians)
py = r * sin(radians)
Line (320, 240)-(320 + px, 240 + py)
Print PX, PY
Angle += 30
Loop until angle > 360
sleepcircle algorithm question - Agamemnus - 07-17-2006
Thanks guys!
I needed this for a custom scenario in a Microsoft game called Rise of Legends, btw.