09-28-2008, 02:43 AM
Again, way too slow, just use the mathematical functions that are already available to you.
You have a number n#, must be > 0
The answer is then b# = LOG(n#) / LOG(10)
Done. No need for loops with stepsize 0.00001.
You have a number n#, must be > 0
The answer is then b# = LOG(n#) / LOG(10)
Done. No need for loops with stepsize 0.00001.