"idiv"ing double words

[rCX]

I'm stuck

Awhile back I asked if there was a way to divide dx:ax by bx and get a double word anwer. (like FFFFFFFFh / Ah = 19999999h) and I got this peice of code.....

Code:

;*dx:ax/bx; dx:ax = answer, cx = remainder*
push ax            ;save ax (lower word)
mov ax,dx        ;higher word into ax so it can be divided
xor dx,dx        ;dx = 0
div bx            ;dx:ax/bx; ax = answer dx = remainder
mov cx,ax        ;save higher word
pop ax            ;get ax, the lower word
div bx            ;dx:ax/bx again
xchg dx,cx        ;extange;dx = higher word cx = remainder

I was wondering if anyone knew how to do the same thing with the "idiv" (divide with sign) function. Thanks.