Algorithm to determine if a number A is a power of B.

[Lithium]

Is this what you were asking?

Code:

input "a = ", a
input "b = ", b

n = a
while ((n / b) = (n \ b))
    n = n / b
    if n = 1 then
        print a; " is a power of"; b
        sleep
        end
    end if
wend

print a; " is NOT a power of"; b
sleep

...only works with integers >= 1...