02-07-2005, 09:33 PM
I guess it is:
So if you are working in an 8 bpp mode, you will have just one integer for width, another one for height and then width * height bytes with the image stored in row-order.
This is just a guess, anyways.
Code:
width 4 bytes (32 bits integer)
height 4 bytes (32 bits integer)
raw image (width * height * bytesperpixel bytes)
So if you are working in an 8 bpp mode, you will have just one integer for width, another one for height and then width * height bytes with the image stored in row-order.
This is just a guess, anyways.
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ComputerEmuzone Games Studio
underBASIC, homegrown musicians
[img]http://www.ojodepez-fanzine.net/almacen/yoghourtslover.png[/i