06-07-2006, 07:42 AM
Quote:No. red_Marvin was talking about y=1/x, WHICH IS A CURVE, and he asked what y would be for x=0: negative or positive infinity? Then you said "t would be both: Y would exist on all possible points of the Y axis, from 0 to positive infinity, and from 0 to negative infinity." Which is incorrect. The curve would never intersect Y, ever, and certainly not at Y=0. Just look at the graph.Zack Wrote:Wrong. He was talking about a line, not a curve. And I never said Y intersected at infinity. A vertical line at x=0 intersects Y everywhere.Radical Raccoon Wrote:100% wrong. The curve never intersects the Y axis, and it certainly doesn't at Y=0!red_Marvin Wrote:If you think division with 0 is valid [and infinite]:It would be both: Y would exist on all possible points of the Y axis, from 0 to positive infinity, and from 0 to negative infinity.
When graphing y=1/x
For x<0 and growing towards 0, y grows to negative infinity.
For x>0 and shrinking(?) towards 0, y grows to positive infinity.
Would y, for x=0, be positively or negatively infinite?
Please, let's not debate this any further. It's not worth my time. Let's just assume that when someone's talking about infinite energy that they mean a really big number.
It just doesn't make sense to say that the x or y axis is intersected "at infinity." Infinity is the concept of a never-ending number, so it can never be reached.
[EDIT]LooseCaboose, here's another violation involved with division by zero. n/n=1, so if n=0, n/n=1. But 0/n always equals 0, so...n=1 or n=0. Of course it should be corrected to n/n=1, nâ 0.
f only life let you press CTRL-Z.
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Freebasic is like QB, except it doesn't suck.
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Freebasic is like QB, except it doesn't suck.