06-16-2006, 08:45 AM
SJ Zero, you're making the same ridiculous assertions about what I said as before. And, if you didn't realize, that was a definite integral that actually made sense, at least to me, which I wasn't sure how to solve. Just because your integration notation is incomprehensible doesn't mean you need to trash talk me... and also you had no sources to back up your result.
Zack, the rate of acceleration remains constant, and so does acceleration.
a is acceleration in "a = 1/C".
Let's say m1 = 5:
a = 1/C
da/dt = 0 (da/dt is the rate of acceleration over time)
Let's say m1 = 10:
a = 1/C (the same...)
da/dt = 0
As you're not yet quite as hopeless as SJ Zero, Zack, I'll dissect your statement:
>In a seperate law, F=ma, and by extension a=F/m, acceleration of an object=force applied/the mass of the object, as the mass increases, the rate of acceleration DECREASES.
Yes, that is true, assuming the force is held CONSTANT.
>So as mass goes up, gravitational force does too
Also true, assuming the acceleration DECREASES.
>but we NEED more force to move a more massive object
Yes, that is correct, assuming acceleration stays constant.
>therefore things of different masses fall at the same speed.
I assume you mean gravitational acceleration here. That would be true, if you somehow reduced something else proportionately-- for instance, if you reduced the mass of the other object, or increased the distance.
Zack, the rate of acceleration remains constant, and so does acceleration.
a is acceleration in "a = 1/C".
Let's say m1 = 5:
a = 1/C
da/dt = 0 (da/dt is the rate of acceleration over time)
Let's say m1 = 10:
a = 1/C (the same...)
da/dt = 0
As you're not yet quite as hopeless as SJ Zero, Zack, I'll dissect your statement:
>In a seperate law, F=ma, and by extension a=F/m, acceleration of an object=force applied/the mass of the object, as the mass increases, the rate of acceleration DECREASES.
Yes, that is true, assuming the force is held CONSTANT.
>So as mass goes up, gravitational force does too
Also true, assuming the acceleration DECREASES.
>but we NEED more force to move a more massive object
Yes, that is correct, assuming acceleration stays constant.
>therefore things of different masses fall at the same speed.
I assume you mean gravitational acceleration here. That would be true, if you somehow reduced something else proportionately-- for instance, if you reduced the mass of the other object, or increased the distance.
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